Practice] //1int a,b;
short int c;
short d=100;
a=d-20;
b=a+d;
c=a+b+d;
d=d-a+c-b;'Vtable
a,2,0
b,2,0
c,2,0
d,2,100
of Vtable
'Vupdate
1,0;2,0
3,0
4,100
1,80
2,180
3,360
4,200
of Vupdate
of Practice
[Practice] //2int a=5;
int b=9;
long int c;
long d;
c=a+b-7;
d=a*b*c;
c=d*d*d;
a=c-d;'Vtable
a,2,5
b,2,9
c,4,0
d,4,0
of Vtable
'Vupdate
1,5
2,9
3,0
4,0
3,7
4,315
3,31255875
1,-5112
of Vupdate
of Practice
[Practice] //3int a=6,b=19;
unsigned int c;
int d;
c=a-b+7;
d=b*c;
a=b+c+d;
b=-a;'Vtable
a,2,6
b,2,19
c,2,0
d,2,0
of Vtable
'Vupdate
1,6;2,19
3,0
4,0
3,65530
4,-114
1,-101
2,101
of Vupdate
of Practice
void main(){
long x,y;
int a,b,c,d;
x=5;
y=6;
a=7;
b=8;
c=x+a;
d=y+b;
printf("c=x+a=%d,d=y+b=%d\n",c,d);
}
将main说明为返回void,即不返回任何类型的值
x,y被定义为long型
a,b,c,d被定义为int型
5->x
6->y
7->a
8->b
x+a->c
y+b->d
显示程序运行结果 of long x,y;
int a,b,c,d;
c=x+a;
d=y+b;
做法] / / 1INT A,B,
短整型C;
短D = 100;
= D-20;
B = AD
C = ABD
D = DA CB,“虚函数表,2, 0
B,2,0
C,2,0
虚函数表的研发,2100
'vupdate
1,0 2,0 3,0
4100
1,80
2180
3360 4200
vupdate
实践
[做法] / / 2INT A = 5;
INT B = 9;
长整型C,D;
C = B-7;
长
D = A * B * C
C = D * D * D;
= CD,“虚函数表,2,5
B,2,9
C,4,0 D,4,0
虚函数表
'vupdate
1,5
2,9
3,0
4,0
3,7
4,315 3,31255875
1,-5112的vupdate
实践
[做法] / / 3int A = 6,B = 19;
unsigned int类型;
INT D;
C = AB 7;
D = B * C;
= BCD;
B =-A; “虚函数表,2,6 B,2,19 C,2,0 D,2,0
虚函数表
'vupdate
1,6 2,19 3,0
4,0
3 65530
4,-114,-101
2,101,
vupdate
实践
无效的主要(){
长的x,y
诠释A,B,C,D,
x = 5;
Y = 6,
= 7;
B = 8;
C = XA;
D = YB
printf的(“C = XA =%d个,D = Yð被定义为int型
5 - > X
6 - > Y
-
- > B
X-> C
Y,B-> D
显示程序运行结果的长x,y;
A,B,C,D,C = XA
D = YB
正在翻譯中..

实践] / / 1int一,二;
短整数丙;
短= 100;
= d-20
;乙=数;
=乙丁;
= a c;'vtable
,2 , 0 2 , 0
乙,丙,2 , 0
,2100
虚函数表
'vupdate
10;2 , 0
块
4100
1 , 80
2180
3360
4200
的vupdate
实践
[做法] / / 2 int = 5;
将= 9;
长整数的;
长的
;丙=一个高档
;丁= * *丙型肝炎
;丙=四* *;
= D;'vtable
,2 , 5
乙,2、9
,4,0
,4,0
虚表
'vupdate
1.5
2、9
块
4,0
7
4315
331255875
1,- 5112
的vupdate
Of Practice
[Practice] //3int a=6, b=19;
unsigned int c;
int D;
c=a-b 7;
d=b*c;
a=b C D;
b=-a;'Vtable
a, 2,6
b, 2,19
c, 2,0
d, 2,0
of, Vtable
'Vupdate
1,6; 2,19
3,0
4,0
365530
4, -114
1, -101
2101
of Vupdate
of Practice
void main (x) {
long, y;
int a, B, C, D;
x=5;
y=6;
a=7;
b=8;
c=x a;
d=y B;
printf ("c=x a=%d, d=y b=%d\n", C, d);
}
will main that for the return of void, which does not return a value of any type of
x, y was defined as long
a, B, c,D was defined as int
5->x
6->y
7->a
8->b
x a->c
y b->d
of long display program running results x, y;
int a, B, C, D;
c=x a;
d=y B;
正在翻譯中..
